douh9817 2015-12-09 18:38
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在laravel中获得一对多的记录

What am I trying?

Get a particular category and it's associated Sub Categories


Category Model

class Category_Model extends Model
{
    protected $table = "tblcategory";
    protected $primaryKey = "CategoryID";
    public $timestamps = false;

    public function Subcategories()
    {
        return $this->hasMany('\App\Models\Skill\SubCategory_Model');
    }
}

Sub Category Model

class SubCategory_Model extends Model
{
    protected $table = "tblsubcategory";
    protected $primaryKey = "SubCategoryID";
    public $timestamps = false;
}

Action Method

public function SubCategories($category)
{
    $Categories = \App\Models\Skill\Category_Model
                  ::where("Category", "=", $category)
                  ->Subcategories;
    dd($Categories);
}

When I run the code. I get below error

SQLSTATE[42S22]: Column not found: 1054 Unknown column 'tblsubcategory.category__model_id' in 'where clause' (SQL: select * from tblsubcategory where tblsubcategory.category__model_id = 1 and tblsubcategory.category__model_id is not null)

  • 写回答

1条回答 默认 最新

  • dongwende1984 2015-12-09 18:53
    关注

    From the comments, it is most likely that your subcategory table doesn't have a category_model_id but likely a category_id. By default, Laravel tries to extrapolate the name of the foreign column from the model name (in this case Category_Model, which explains the category_model_id. Changing the class to:

    class Category_Model extends Model
    {
        protected $table = "tblcategory";
        protected $primaryKey = "CategoryID";
        public $timestamps = false;
    
        public function Subcategories()
        {
            return $this->hasMany('\App\Models\Skill\SubCategory_Model', 'category_id')->get(); // Or whatever the column is actually called
        }
    }
    

    should solve the issue.

    To return both the category object and its subcategories, change the action code to:

    public function SubCategories($category)
    {
        $Categories = \App\Models\Skill\Category_Model
                      ::where("Category", "=", $category)
                      ->with("Subcategories")
                      ->first();
        dd($Categories);
    } 
    

    The $Categories should also now contain a Subcategories object, accessed via $Categories->Subcategories, which should return a collection of Subcategory objects. If you wanted to see each one, you would loop through with a foreach

    foreach($Categories->Subcategories AS $Subcategory){
      echo $Subcategory->name;
      // etc etc.
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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