来自URL的Json in PHP

Question

I'm trying to display some elements from some json data at the following URL using the following code, but it isn't displaying anything. Any ideas what I'm doing wrong?

<?php 

$url="http://fbclaurel.onthecity.org/plaza/events?format=json";

$data = file_get_contents($url);
$json = json_decode($data);

foreach($json->"global_event" as $row)
{
    foreach($row as $key => $val)
    {
       echo $key . ': ' . $val;
       echo '<br>';
    }
}

?>

Answer 1

You actually have a syntax error that is probably hidden due to your configured error reporting / display settings. It would be something like this

PHP Parse error: syntax error, unexpected '"global_event"' (T_CONSTANT_ENCAPSED_STRING), expecting identifier (T_STRING) or variable (T_VARIABLE) or '{' or '$'

When developing, I recommend you always have the following properties in php.ini

display_errors = On
error_reporting = E_ALL

Update

I've just checked the data from that API and it returns an array. Each array entry is an object with a single global_event property that is itself, another object. I imagine you're going to need something like this to iterate...

$json = json_decode($data, true);
// the second "true" argument forces an array format result.
// I find it more appropriate when iterate keys or when keys
// might be invalid property names.

foreach ($json as $obj) {
    $globalEvent = $obj['global_event'];

    // now $globalEvent is an array with keys such as
    // addresses, body, created_at, ending_at, etc.
    // Note that few of these properties are simple, scalar values (like strings),
    // most are arrays themselves

    // display example...
    echo 'title: ', htmlspecialchars($globalEvent['title']), '<br>',
         'short_url: ', htmlspecialchars($globalEvent['short_url']), '<br>';
}