duanqi6274 2012-07-31 14:41
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PHP简单的html dom,试图获取非对象的属性

I get the next notice when firing a specific function:

Trying to get property of non-object in...

My function:

private function rate($form)
{
    $score = 0;

    $count = $form->find('input')->length;
    $score += ($count >= 2 && $count <= 5) ? INPUT_COUNT_RATE : 0;

    $count = $form->find('textarea')->length;
    $score += $count == 1 ? TEXTAREA_COUNT_RATE : 0;

    return $score;
}

The problematic lines are the lines with the find function.

A var_dump of $form returns:

object(simple_html_dom_node)[1062]...

What could be the problem?

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1条回答 默认 最新

  • dtlrp119999 2012-07-31 14:44
    关注

    ->find() returns either an array of matched nodes, or null. You can't call ->length on find results, because the results are not an object. Try

    $nodes = $form->find(...);
    $count = count($nodes);
    
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