duanjue9889 2012-05-07 16:45
浏览 24
已采纳

如何根据$ variable值触发查询?

please excuse me if i am not stating this correctly or using correct terminology since i am new to php development.

I have a page called photos.php and i want to dos something like photos.php?type=me and photos.php?type=friends. As you can infer, with type=me i want to show my photos and with type=friends i want to display friends' photos. So i want to do something like:

if $value == $me trigger type=me query and if $value == $friends trigger query to 
display only friends' photos.
  • 写回答

2条回答 默认 最新

  • donglie7268 2012-05-07 16:47
    关注

    It's as simple as you wrote:

    if ($_GET['type'] == 'me') {
        $sql = 'me query';
    } else if ($_GET['type'] == 'friends') {
        $sql = 'friends query';
    }
    

    Queries depends on your database structure.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥20 关于多单片机模块化的一些问题
  • ¥30 seata使用出现报错,其他服务找不到seata
  • ¥35 引用csv数据文件(4列1800行),通过高斯-赛德尔法拟合曲线,在选取(每五十点取1点)数据,求该数据点的曲率中心。
  • ¥20 程序只发送0X01,串口助手显示不正确,配置看了没有问题115200-8-1-no,如何解决?
  • ¥15 Google speech command 数据集获取
  • ¥15 vue3+element-plus页面崩溃
  • ¥15 像这种代码要怎么跑起来?
  • ¥15 安卓C读取/dev/fastpipe屏幕像素数据
  • ¥15 pyqt5tools安装失败
  • ¥15 mmdetection