dongxiangshen7916 2011-04-13 18:27
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通过引用分配失败,语法错误[关闭]

I have a class instance $obj = new class. obj is actually a variable from another object so it's more like $obj1->obj2->obj3 = new class. This is making my code a little confusing so I want to do something like:

$var =& $obj1->obj2->obj3 = new class

and then start using this instance as

$var->method() or $var->name = 'abc'.

When using it like $var = $obj1->obj2->obj3 = new class it works just fine but I was thinking about the memory I could save (as the object is quite large and duplicating it would not be advisable). I'm not sure if this is an issue or if it actually necessary to assign by reference or if PHP takes this into consideration.

I forgot to mention, using $var =& $obj1->obj2->obj3 = new class results in:

Parse error: syntax error, unexpected '='

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  • doutongxuan1614 2011-04-13 18:33
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    When you do

    $var = new stdClass();
    $var2 = $var; 
    

    $var2 is actually a reference to $var. This is because PHP passes classes by reference. So you aren't actually making a new copy. So you can assign it to your shorter variable and reduce the typing.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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