日期错误解决方案

Question

This is my program :

$newEndingDate = strtotime(date("Y-m-d", strtotime($row['startdate']))."+1 year");
echo $newEndingDate;

this is my error

1332441000

whats the error

Answer 1

The strtotime() function returns an UNIX Timestamp : the number of seconds since 1970-01-01.

The number you are getting is not an error : it just means that 1332441000 seconds have passed since 1970.

If necessary, you can use the date() function to format that timestamp, to get a string that looks a bit more user-friendly.

For instance :

echo date('Y-m-d H:i:s', $newEndingDate);

should get you the following result :

2012-03-22 19:30:00