dqpu4988 2016-04-08 05:18
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Json_decode返回字符串(0)“”

I am trying to pass data from ios to server.

Php code :

<?php
   $inputJSON = file_get_contents('php://input');
   $data = json_decode($inputJSON, TRUE);
   var_dump($data);
?>

This gives me string(0) "". I don't know whats the meaning of this.

        echo $inputJSON; gives nothing 
       var_dump($inputJSON); returns  string(0) ""

When i print the json-string it gives me a valid string

Please find the full codes of this problem in another question of mine

Cannot able to access json array in php , it returns null and Warning: Invalid argument supplied for foreach()

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3条回答 默认 最新

  • dounielong7728 2016-04-08 06:37
    关注

    With God Grace solved my problem-

    pass true to convert objects to associative arrays, so accessing numeric/associative array like this.

    $var = $data[0]['key'];
    

    Then we use a combination of numeric and associative array syntax to access the desired element in multidimensional array.

    But if i trying to var_dump($data); is retun null.

    Reference tutorial: http://www.dyn-web.com/tutorials/php-js/json/decode.php

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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