我在理解WordPress字符串中的PHP变量语法时遇到了一些问题

Question

I have the following line in some code I am trying to modify to include an image from my theme directory.

protected $_branding = 'Site Design by <a href="http://www.mysite.com">MySite</a>.';

So, what I want is:

protected $_branding = 'Site Design by <a href="http://www.mysite.com"><img src="(((My ThemeFolder)))/images/myimage.png" style="vertical-align:text-bottom;"/>MySite</a>.';

What is returned seems to output exactly what is inside the parent quotes. So, I am assuming this is some kind of string. So, how do I make it include a PHP variable to get my theme folder without having to hard code it?

Thank you

Answer 1

You want get_template_directory_uri()

protected $_branding = 'Site Design by <a href="http://www.mysite.com"><img src="' . get_template_directory_uri() . '/images/myimage.png" style="vertical-align:text-bottom;"/>MySite</a>.';

See http://codex.wordpress.org/Function_Reference/get_template_directory_uri for the documentation.