基于具有不同元素的其他数组过滤php数组

Question

I have an array $items as such:

[0] => Array (
  [itemid] => 8
  [name] => A
  [rating] => 9.5
)
[1] => Array (
  [itemid] => 41
  [name] => B
  [rating] => 9.5
)

and another array $array as such:

[0] => Array (
  [itemid] => 458
  [name] => C
  [rating] => 9.603 
)
[1] => Array (
  [itemid] => 460
  [name] => D
  [rating] => 9.603
)
[2] => Array (
  [itemid] => 8
  [name] => A
  [rating] => 9.523
)
[3] => Array (
  [itemid] => 41
  [name] => B
  [rating] => 9.2
)

What I would like to do is return the array $array, but with all the elements from $items filtered out. In this case it would return $array, but without [2] and [3].

I've tried with array_diff(), but the rating can change from one array to the other, so the elements in the one array are not always the same as in the other array.

How do I go about this?

Answer 1

Is this what you're looking for?

<?php

$arr1 = [];
$arr1[] = [ "itemid" => 8, "name" => "A", "rating" => 9.5 ];
$arr1[] = [ "itemid" => 41, "name" => "B", "rating" => 9.5 ];

$arr2 = [];
$arr2[] = [ "itemid" => 458, "name" => "C", "rating" => 9.603 ];
$arr2[] = [ "itemid" => 460, "name" => "D", "rating" => 9.603 ];
$arr2[] = [ "itemid" => 8, "name" => "A", "rating" => 9.523 ];
$arr2[] = [ "itemid" => 41, "name" => "B", "rating" => 9.2 ];


function compare_by_itemid($a, $b) {
    return $a['itemid'] - $b['itemid'];
}

var_dump(array_udiff($arr2,$arr1,'compare_by_itemid'));