douran6443 2017-07-27 22:31
浏览 35
已采纳

如何在laravel中使用特殊消息管理特殊错误

I'm using laravel 5.4. and I need handle some error. imagine user logged in and opened two windows (his profile). When user click on logout in a window, we have still logout button in another window, and by clicking on that, laravel will show csrf_token error page.

My logout in not ajax and its with submitting a form to /logout how can I handle this error with special message or redirect to home without error from logout controller? (not all of csrf_token errors, just from that controller).

logout form :

i will submit this form by clicking on logout button using jquery:

<form id="logout-form" action="/logout" method="POST" style="display: none;">
    <input type="hidden" name="_token" :value="token">
</form>

And the logout method in controller :

public function logout(Request $request)
{
    $this->guard()->logout();
    $request->session()->flush();
    $request->session()->regenerate();
    return redirect('/');
}
  • 写回答

2条回答 默认 最新

  • douchi5822 2017-07-28 14:17
    关注

    in App\Exceptions\Handler.php Return the user to the form with a new valid CSRF token, so the page will refreshed and logout button will not exist.

    public function render($request, Exception $exception)
    { 
       if($exception instanceof TokenMismatchException)
       { 
          return redirect()
                   ->back()
                   ->with('your msg');
       }
       return parent::render($request, $exception); 
    }
    

    this looking like, page was refreshed.

    Don't Replace POST with Get. It will not Safe And Standard.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?