如何检查数字（浮点数或整数）是否在一个范围内（0 - 100）

Question

I'm looking for the fastest way to get this test. So functions, operands and everything else is allowed. I tried with the following regex (I'm not an expert):

0\.[0-9]+|100\.0+|100|[1-9]\d{0,1}\.{0,1}[0-9]+

It works except that it erroneously accept 0.0 or 0.000000 and so on. Also it's not the most appropriated and fastest way.

(if anybody wants to fix the regex to don't allow those 0.00 values it would be appreciated)`

Answer 1

No need for regex:

if (is_numeric($val) && $val > 0 && $val <= 100)
{
    echo '$val is number (int or float) between 0 and 100';
}

Demo

Update

It turns out you're getting the numeric values from a string. In that case, it would be best to extract all of them using a regex, something like:

if (preg_match_all('/\d+\.?\d*/', $string, $allNumbers))
{
    $valid = [];
    foreach ($allNumbers[0] as $num)
    {
        if ($num > 0 && $num <= 100)
            $valid[] = $num;
    }
}

You can leave out the is_numeric check, because the matched strings are guaranteed to be numeric anyway...