douzhanhui5662 2015-01-04 15:06
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PHP preg_replace意外输出以匹配特殊字符'$'

I got an Issue in a PHP Script, in case of this function for regular expression matching and replacing. I've tested my regular Expression on www.regex101.com and got always expected results, but not in PHP.

I use this Pattern inside the Function:

$matchedName = preg_replace("/^(\$|\(.+\))( ?)/", "", $name);

To match Character '$' or any Expression in Brackets at the Begin and delete this. Any Input with Brackets works well.

$name = "$ blah";
$matchedName = preg_replace("/^(\$|\(.+\))( ?)/", "", $name);
var_dump($matchedName);

Output:
string(8) "$ blah"

Now, got i missunderstood something? Or got this Function really an Issue in Case of the '$' Character?

Thanks for any Replies

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  • drix47193 2015-01-04 15:33
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    $re = "/^(\\$|\\(.+\\))( ?)/im";
    $str = "\$ blah";
    $subst = "";
    
    $result = preg_replace($re, $subst, $str);
    

    Try this.This is working.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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