php文件获取内容，搜索和显示

Question

I have some content it another website that i would like to show my users, i use file get content function.

but i dont need to display the whole content, just two rows, The current product and the next product. the content is arranged with html tables.

my code:

   <?php
$url = "http://the second website.com";
$str = file_get_contents($url);

$lines = explode("<tr>", $str);

foreach ($lines as $newline) {
    echo '<tr>' . $newline . '</tr>'; -- This prints all lines.
}
?>

How to echo only the specific lines ? My needed line are start with the strings "current product" and "next product". Do i need to use an array ? or do in need to use a search string function ?

Thanks all.

Answer 1

You could do this with preg_match_all like this:

$table = <<<EOS
<table>
   <tr>
      <td>1.1</td>
      <td>1.2</td>
   </tr>
   <tr>
      <td>2.1</td>
      <td>2.2</td>
   </tr>
</table>
EOS;

preg_match_all('/<tr.*?>(.*?)<\/tr>/si', $table, $matches);

print_r($matches[1]);

The output is:

Array
(
    [0] => 
      <td>1.1</td>
      <td>1.2</td>

    [1] => 
      <td>2.1</td>
      <td>2.2</td>

)

You could also read about PHP DOM Inspector.