如何解码json并将json中的值设置为php可用？

Question

i have json $json like this

{"name":"peter","availability":"available"}

i want to decode and set value to php available and echo but not any show ?, i use this code

<?PHP
                 $decode = json_decode($json, true);
                 $availability = $decode[availability];
                 echo $availability;  
?>

where is wrong ?

Answer 1

Use as

$availability = $decode["availability"];

If you use

$availability = $decode[availability];

It will raise a notice as

Notice: Use of undefined constant availability - assumed 'availability'

However your code is correct is should display the value with the above notice unless the $json string is not the one you have added.

Your code

<?php 
$arr = array('name' => peter, 'availability' => available); 
$json = json_encode($arr); 
$decode = json_decode($json, true); 
$availability = $json_decode[availability]; 
print_r($json); 
echo $availability; 
?>

Now this is what you are doing

$decode = json_decode($json, true); 
$availability = $json_decode[availability]; 

You are using a different array name $json_decode instead of $decode

So the correct way is

$arr = array('name' => 'peter', 'availability' => 'available'); 
$json = json_encode($arr); 
$decode = json_decode($json, true); 
$availability = $decode['availability']; //print_r($json); 
echo $availability;