即使在成功的ajax帖子之后也无法显示div弹出窗口

Question

I have a div

<div id="pop2" class="pop-up1" style="display:none;">
  <div class="popBox1">
    <div class="popScroll1">
      <h2></h2>
      <p id="p1_id"></p>
    </div>
    <a href="#links" class="close"><span>Close</span></span></a>
  </div>
  <a href="#links" class="lightbox1">Back to links</a>
</div>

I have an external file edit_invoice_details.php in which I want to post some data which I am doing through this jquery function

<script>
    $(document).ready(function(){
    $('table tbody tr').dblclick(function(){
        //alert($("#myId2").text());
        //showeditDiv($( "#myId2" ).text());
        var invid=$("#myId2").text();
        var pid=$("myId").text();
        var dataString = 'inv_id='+ invid+'prod_id='+pid;
        $.ajax({
        type: "POST",
        url: "edit_invoice_details.php",
        data: dataString,
        cache: false,
        success: function(html)
        {           
            alert("success");
            $("#pop2").show();
            $("#p1_id").html(html).show();
        }
        });
    });
});
</script>

I want such a table such that when someone double clicks on it the div should open. Success alert is working fine. but I am not able to show that div. The divs content should be edit_invoice_details.php. Response text maybe

Any help is appreciated

Answer 1

I think you need to use a & here:

var dataString = 'inv_id='+ invid+'&prod_id='+pid;