php printf不适用于<li type =“1”>

Question

I have php prinf and doesn't work with <li type="1">. It works only with chrome browser, what can i do to make it work with all browsers?

My php code is very long and ill provide shorter version:

sample code is like this:

<ul>
<table>
$result = mysql_query("........",$db);

if(mysql_num_rows($result) > 0)
{
    $myrow = mysql_fetch_array($result);
do
{
    printf ("

<tr><td><li type="1">%s</li></td></tr>",$myrow["var"]);
}
while ($myrow = mysql_fetch_array($result));    
}
else
{
    echo "<p align='center'>error...</p>";
}

</table></ul>

Answer 1

from the sample code provided you have messed up the tag order. try this. Note i have moved the tag orders. Hope this is what you want to achieve. too unclear from the question.

<table>
<?php
$result = mysql_query("........",$db);

if(mysql_num_rows($result) > 0)
{
    echo '<tr><td><ul>';
    $myrow = mysql_fetch_array($result);
    do
    {
        printf ("<li type=\"1\">%s</li>",$myrow["var"]);
    }
    while ($myrow = mysql_fetch_array($result)); 
    echo '</ul></td></tr>';
}
else
{
    echo "<p align='center'>error...</p>";
}
?>
</table>

tag order should be. you cannot insert <table> as a child of <ul>. <ul> can have only <li> as child.

<table>
   <tr>
       <td>
           <ul>
               <li>...</li>
           </ul>
       </td>
   </tr>
</table>

Edit:
You may not need the <ul>...</ul> tags. you can do it with simple table. Try this

<?php
$result = mysql_query("........",$db);

if(mysql_num_rows($result) > 0)
{
    echo '<table>';
    $rownum=1; //just a counter here, if have other real value then use it
    $myrow = mysql_fetch_array($result);
    do
    {
        printf ("<tr><td>%d</td><td>%s</td></tr>", $rownum, $myrow["var"]);
        $rownum++;
    }
    while ($myrow = mysql_fetch_array($result)); 
    echo '</table>';
}
else
{
    echo "<p align='center'>error...</p>";
}
?>

and if you want to do it with just ordered list you can do it like the following

<?php
$result = mysql_query("........",$db);

if(mysql_num_rows($result) > 0)
{
    echo '<ol>';
    $myrow = mysql_fetch_array($result);
    do
    {
        printf ("<li>%s</li>", $myrow["var"]);
        $rownum++;
    }
    while ($myrow = mysql_fetch_array($result)); 
    echo '</ol>';
}
else
{
    echo "<p align='center'>error...</p>";
}

Note: the type attribute of <li> is deprecated in HTML 4.01. and is not supported in HTML 5.