PHP foreach给出了错误的结果

Question

I've searched for this for quite a while now and I cannot figure out why my code isn't working how it appears. I'm not sure if I'm having a block or anything but here goes:

$start = 1;
$sstart = strval($start);
$scan = scandir('upload');
$result = null;
while($result==null)
    {
        foreach($scan as $value)
        {
            if(strpos($value,$start) == false)
                {
                    $result = $start;
                    break 2;
                }
            else
                {
                    $start = $start + 1;
                    break;
                }
        }
    }

Essentially, I want to scan my directory 'upload' for any files with the number held in $start. If this value ISN'T found, then $result takes the value of $start and the while() loop ends. Otherwise I increment $start and proceed to check every file in the directory again.

Now I have a very similar function like this running on another page that works flawlessly. However this always seems to stop at 1.

There is DEFINITELY a file in my upload folder called showreel1.wmv and it definitely scans this. (Have echo'd the scandir array) However, it never seems to switch to the else block but carries on setting $result as if it never found the value '1'.

I have also tried using $sstart in the strpos() function and it has no effect, this of course changes the value of $start into a string.

Can you guys shed any light on this for me please?

Answer 1

I hope I understood what you're trying to do, try with this:

while($result === null)
{
    $found = false;
    foreach($scan as $value)
    {
        if(strpos($value,$start) !== false)
        {
            $found = true;
            $start = $start + 1;
            break;
        }
    }

    if(!$found)
    {
        $result = $start;
        break;
    }
}

By the way, you should learn how to use === operator, it's essential to correctly use strpos()