dqlm80253 2012-11-20 04:18
浏览 67
已采纳

加载异步数据后获取网页源

I am trying to retrieve the page source of a page on another domain after it has loaded the content it gathers asynchronously.

I have tried PHP's file_get_contents, but this does not obtain the source code after the asynchronous data is loaded.

Any help is appreciated.

  • 写回答

1条回答 默认 最新

  • douying7289 2012-11-20 04:24
    关注

    There is no way you can do that using PHP's file_get_contents or even using cURL. You have to look into other options.

    Like, PHP's V8js module: http://php.net/manual/en/book.v8js.php

    or you can try to use Selenium.

    What you are looking for is basically a way to execute the JavaScript from with in php.

    Ofcourse you could always peep into the asynchronous requests on the page, and make your own requests too!

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 (标签-Python|关键词-socket)
  • ¥15 keil里为什么main.c定义的函数在it.c调用不了
  • ¥50 切换TabTip键盘的输入法
  • ¥15 可否在不同线程中调用封装数据库操作的类
  • ¥15 微带串馈天线阵列每个阵元宽度计算
  • ¥15 keil的map文件中Image component sizes各项意思
  • ¥20 求个正点原子stm32f407开发版的贪吃蛇游戏
  • ¥15 划分vlan后,链路不通了?
  • ¥20 求各位懂行的人,注册表能不能看到usb使用得具体信息,干了什么,传输了什么数据
  • ¥15 Vue3 大型图片数据拖动排序