php - 秒离开时间？

Question

I'm trying to format a date to say how much time is left (in a readable format) from how many seconds are left:

<?php
    $seconds = 23414;
    $date = new DateTime();
    $date->setTime(0, 0, $seconds);
    echo $date->format('z G:i:s');
?>

This example might output something like: 344 11:46:45 which is not what I'd like. It should say something like 6 days, 4:12:36. I just don't see anything here: http://www.php.net/manual/en/function.date.php that would help me format it correctly. Ideas?

Answer 1

I don't know of anything built in, but it's easy enough to write:

function formatSeconds($secondsLeft) {

  $minuteInSeconds = 60;
  $hourInSeconds = $minuteInSeconds * 60;
  $dayInSeconds = $hourInSeconds * 24;

  $days = floor($secondsLeft / $dayInSeconds);
  $secondsLeft = $secondsLeft % $dayInSeconds;

  $hours = floor($secondsLeft / $hourInSeconds);
  $secondsLeft = $secondsLeft % $hourInSeconds;

  $minutes= floor($secondsLeft / $minuteInSeconds);

  $seconds = $secondsLeft % $minuteInSeconds;

  $timeComponents = array();

  if ($days > 0) {
    $timeComponents[] = $days . " day" . ($days > 1 ? "s" : "");
  }

  if ($hours > 0) {
    $timeComponents[] = $hours . " hour" . ($hours > 1 ? "s" : "");
  }

  if ($minutes > 0) {
    $timeComponents[] = $minutes . " minute" . ($minutes > 1 ? "s" : "");
  }

  if ($seconds > 0) {
    $timeComponents[] = $seconds . " second" . ($seconds > 1 ? "s" : "");
  }

  if (count($timeComponents) > 0) {
    $formattedTimeRemaining = implode(", ", $timeComponents);
    $formattedTimeRemaining = trim($formattedTimeRemaining);
  } else {
    $formattedTimeRemaining = "No time remaining.";
  }

  return $formattedTimeRemaining;

}

I haven't tested it thoroughly, but the tests I did run worked fine. You might want to test it yourself a bit before using it.