检查我的应用程序环境设置的更好方法？

Question

I am building an application and I have constant called ENVIRONMENT_SETTING. As I am currently developing the application I have it as define('ENVIRONMENT_SETTING', 'dev');

Then I am checking at the top of the file what it is. I am currently doing if statements like so:

if (defined('ENVIRONMENT_SETTING'))
{
    if (ENVIRONMENT_SETTING == 'dev')
    {
        error_reporting(E_ALL);
    }
    elseif (ENVIRONMENT_SETTING == 'test' || ENVIRONMENT_SETTING == 'prod')
    {
       error_reporting(0);
    }
}
else
{
    die('Environment setting not set.');
}

This to me though seems like a bit too much code for such a simple check. Is there a better way to do this?

Answer 1

Well I personally would use a switch statement. It's much more concise. In your case I would do the following:

defined('ENVIRONMENT_SETTING') ? NULL : define('ENVIRONMENT_SETTING', 'dev');
if (defined('ENVIRONMENT_SETTING'))
{
    switch (ENVIRONMENT_SETTING)
    {
        case 'dev':
            error_reporting(E_ALL);

        break;

        case 'test':
        case 'prod':
            error_reporting(0);

        break;

        default:
            exit('Environment setting not set.');
    }
}