dongmu1951 2014-07-18 03:30
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尝试循环遍历数组以返回文件路径名称

I'm new to PHP so please bear with me. I'm practicing coding for real situations so I mimicked a database by storing my image paths in an associate array so that I could create a function that would return the path name and thus just call the function to echo out my image.

My problem is it's only returning the last item in my array. I need the function to loop through the array for every item and return the file path so that I can store it in $images and then echo that out where I need to.

CODE:

<?php


$images = array(
array('name'  => 'image_00', 'path'  =>  'images/image-00.jpg'),
array('name'  => 'image_01', 'path'  =>  'images/image-01.jpg'),
array('name'  => 'image_02', 'path'  =>  'images/image-02.jpg')
);

function returnPath($filename, $arr) {

    $path = array();

    foreach ($arr as $file) {
        $path = $file[$filename];
    }

    return $path;
}

$images = returnPath('path', $images);

?>

<!DOCTYPE html>
<html>
<head>
    <title>Images Project</title>
</head>
<body>
    <img src="<?php echo $images; ?>"/>
</body>
</html>
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2条回答 默认 最新

  • dpiz9879 2014-07-18 03:33
    关注

    The issue is that you're over-writing the $path variable in your returnPath function.

    What you want is this:

    foreach ($arr as $file) {
    $path[] = $file[$filename];
}

    Which in turn will give you an array of the paths that you can itterate over like this:

    $images = returnPath('path', $images);

<body>
<?php 
foreach($images as $image) {
    echo '<img src="'. $image .'" />';
}
?>
</body>

    I also strongly agree with koala_dev's comment. The function isn't really effective/useful.

    Since you already have the $images array, just:

    foreach($images as $img) {
    echo $img['path'];
}

    Or even make the function useful by returning formatted html <img> tags to print to the HTML DOM :-)

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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