检查“前一个”元素是否为'x'（组合prev（）和end（））

Question

I have an array of integers in php and what I'd like to do is check if the before the last element is equal to 'x'. I've tried this:

if(prev(end($array)) == $x)

But it returns an error Warning: prev() expects parameter 1 to be array, string given given the fact end returns the last element instead of a pointer. Any idea on this one?

Answer 1

this index count($array)-2 could help :

if($array[count($array)-2] == $x)