如何检查收音机是否被检查？ [关闭]

Question

How to check if radio button is checked after post?

Code on my radio button

<?php if(isset($_POST['Itemtype']) && $_POST['Itemtype'] == 'Ingredient') echo 'checked="checked" ';?>
<?php if(isset($_POST['Itemtype']) && $_POST['Itemtype'] == 'Miscellaneous') echo 'checked="checked" ';?>

code to check my radio:

$Itemtype = $_POST["Itemtype"];

if($_POST["Itemtype"] == "Ingredient")
{
    $try2 = "ingred. working";
]
elseif($_POST["Itemtype"] == "Miscellaneous")
{
    $try2 = "misc. working";
}
else
{
    $errormsg = "error5";
}

If I don't select a radio button it says "syntax error: undefined Index Itemtype" keeps aiming at the $Itemtype = $_POST["Itemtype"];

and if i select radio button it doesn't return checked on the selected radio button.

anyone can give me helping hand on this thanks.

Answer 1

<?  
    $_POST['Itemtype'] = "Ingredient";
    if(isset($_POST['Itemtype'])) {
        $Itemtype = $_POST["Itemtype"]; 
        if($_POST["Itemtype"] == "Ingredient") {
            $try2 = "ingred. working"; 
        }elseif($_POST["Itemtype"] == "Miscellaneous"){
            $try2 = "misc. working"; 
        } 
    } else { $errormsg = 'error5'; }
    echo $try2;
    echo $errormsg;
?>

I forced the Itemtype for debugging reasons... This would show your logic works... Question I have is are you echoing out your $try2....