douluan5738 2013-01-26 05:41
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加入两个表后用于打印标题和计数ID的SQL语句

SELECT b.post_title
     , a.post_id
     , Deriv1.Count
FROM  wp_posts b
    , wp_postmeta a
LEFT OUTER JOIN (    
   SELECT meta_value, COUNT( * ) AS Count
   FROM  wp_postmeta
   GROUP BY meta_value
   ) Deriv1 
ON a.post_id = Deriv1.meta_value
WHERE a.meta_value = 1
  AND a.meta_key = 'type-select' 
  AND b.post_status = 'publish'
  and post_type = 'car-cc'

Current problem of the SQl STATEMENT is when i supply meta_value =1 it is fetching all values i.e. post_id which do not have meta_value =1 is also listed.

http://sqlfiddle.com/#!2/1115a7/1

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  • duandaishi9268 2013-01-26 05:51
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    I think the problem is you're not joining on the wp_posts table and wp_postmeta table. Add this to your WHERE clause:

    AND a.post_id = b.ID
    

    Alternatively, just do an INNER JOIN on the two tables:

    SELECT b.post_title
         , a.post_id
         , Deriv1.Count
    FROM  wp_posts b INNER JOIN 
            wp_postmeta a ON a.post_id = b.ID
    LEFT OUTER JOIN (    
       SELECT meta_value, COUNT( * ) AS Count
       FROM  wp_postmeta
       GROUP BY meta_value
       ) Deriv1 
    ON a.post_id = Deriv1.meta_value
    WHERE a.meta_value = 1
      AND a.meta_key = 'type-select' 
      AND b.post_status = 'publish'
      and post_type = 'car-cc'
    

    BTW -- Did you want the count for each group? If so, your query can be simplified:

    SELECT b.post_title, a.post_id, COUNT( * ) as Total
    FROM  wp_posts b INNER JOIN 
                wp_postmeta a ON a.post_id = b.ID
        WHERE a.meta_value = 1
          AND a.meta_key = 'type-select' 
          AND b.post_status = 'publish'
          and post_type = 'car-cc'
    GROUP BY b.post_title, a.post_id
    

    Here is some updated fiddle. Wasn't sure of your desired output.

    Good luck.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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