douhui7136 2013-01-18 19:29
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通过创建另一个对象返回对另一个对象的引用(令人困惑)

I am made a class that is called SQL_Connection. The purpose of this class is to return a reference ($con) to the calling variable. Example: $conRef = new SQL_Connection(); Where $conRef would now be a reference of $con and not an instance of SQL_Connection(), if this is possible of course.

The construct function at the end does return $con;, I presume this may be the issue :/

Thanks.

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  • doutian4046 2013-01-18 19:32
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    Using new implies that you know the exact type of the object you want to construct. The pattern you want to use is a factory method, not a constructor. For example:

    class SQL_Connection
    {
        public static function create()
        {
            $con = new Other_SQL_Connection();
            return $con;
        }
    }
    

    Then invoke SQL_Connection::create() elsewhere to obtain the object reference.

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