dsieyx2015 2012-09-25 23:00
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PHP - 在第二个爆炸阵列之后回显所有内容

I've got a script that explodes an input, see below:

$message = explode(" ", $_GET['message']);
switch($message[0])
{
    case "/commands":
        echo "N/A";
    break;
    case "/mute":
        $player = $message[1];
        $time = $message[2]; // seconds
        $reason = $message[3];
        echo "Mute {$player} for {$time} seconds because {$reason}";
    break;
    default:
        echo "Invalid command";
    break;
}

I've stumbled into an issue, say the user was to use "/mute Steve 500 For being an idiot" - it would return to me "Mute Steve for 500 seconds because For" instead of providing me with the full reason, because I've used $message[3], I'm asking you this:

How do I return everything after $message[2]?

Would I have to run a foreach loop, combining all the words together, or is there an easier method?

Sorry if it's hard to understand, I tried explaining the best I could, but it's a hard topic to explain.

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3条回答 默认 最新

  • drgwsx8405 2012-09-25 23:05
    关注

    You can accomplish that easily with array_slice - http://php.net/manual/en/function.array-slice.php

    In your case,

    $reason = implode(' ', array_slice($message, 3));
    
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