dongzhao4036 2011-02-11 01:17
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php 2维数组检索值?

$useridtofind= 123;

$users=array();

while ($data = mysql_fetch_array ($result))
{

        $userid = $data['userid'];
    $age = $data['age'];
    $gender = $data['gender'];
    $dob = $data['dob'];

    $users[$userid] => array(
        'age'=> $age, 
        'gender'=> $gender, 
        'dob' => $dob
        )
}


$useridtofind=123;

for($v=0; $v< count($users); $v++)
{
    if($users[$v]== $useridtofind)
    {
        //how to go with grab value of age, gender, dob  here?      
    }
}
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2条回答 默认 最新

  • doudilin1225 2011-02-11 01:21
    关注

    You seem to be using the user id as the index of the user in the array. If this is the case, you shouldn't be using a for loop, you should just check if the key exists within the array:

    $useridtofind = 123;
    
    if (array_key_exists($useridtofind, $users)) {
      $user = $users[$useridtofind];
    
      echo "User exists: ", $user['age'], '/', $user['gender'], '/', $user['dob'];
    } else {
      echo "User doesn't exist";
    }
    
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