$useridtofind= 123;
$users=array();
while ($data = mysql_fetch_array ($result))
{
$userid = $data['userid'];
$age = $data['age'];
$gender = $data['gender'];
$dob = $data['dob'];
$users[$userid] => array(
'age'=> $age,
'gender'=> $gender,
'dob' => $dob
)
}
$useridtofind=123;
for($v=0; $v< count($users); $v++)
{
if($users[$v]== $useridtofind)
{
//how to go with grab value of age, gender, dob here?
}
}
php 2维数组检索值?
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2条回答 默认 最新
- doudilin1225 2011-02-11 01:21关注
You seem to be using the user id as the index of the user in the array. If this is the case, you shouldn't be using a
for
loop, you should just check if the key exists within the array:$useridtofind = 123; if (array_key_exists($useridtofind, $users)) { $user = $users[$useridtofind]; echo "User exists: ", $user['age'], '/', $user['gender'], '/', $user['dob']; } else { echo "User doesn't exist"; }
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