如何使用php获取URL最后一部分

Question

I was searching for solutions to display the current URL of the page, and I found a few ones but I don't know how to implement them and call them, so this was the best solution I've found for me because it already has the echo thingy.

function curPageURL() {
     $pageURL = 'http';
     if ($_SERVER["HTTPS"] == "on") {$pageURL .= "s";}
     $pageURL .= "://";
     if ($_SERVER["SERVER_PORT"] != "80") {
      $pageURL .= $_SERVER["SERVER_NAME"].":".$_SERVER["SERVER_PORT"].$_SERVER["REQUEST_URI"];
     } else {
      $pageURL .= $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"];
     }
     return $pageURL;
    }

And to call it, I'm calling it like this

echo curPageURL();

But I want to get only the last part of the URL, for exemple:

http://stackoverflow.com/posts/29237151/thequestion

I want to get thequestion part of the URL. how can I do this?

Answer 1

As stated in the comments, the best way is to explode() then array_pop() your URL.

Like so:

function curPageURL() {

    $url = $_SERVER['REQUEST_URI'];
    $url = explode('/', $url);
    $lastPart = array_pop($url);

    return $lastPart;
}

@Vineet answer is suitable too.