在PHP中创建XML输出

Question

I am trying to create an XML file output in PHP for a remote phone book on an IP Phone, here is the code i have:

<?php
$conn=mysql_connect("localhost","user","********");
mysql_select_db("db_name",$conn);

header("Content-Type: text/xml");
header("Connection: close");
header("Expires: -1");
?>

<YealinkIPPhoneDirectory>
<?php
$output='<YealinkIPPhoneDirectory>
';
$sql="SELECT * from contacts ";
$rs=mysql_query($sql,$conn);
while($result=mysql_fetch_array($rs)) {
    $output .= "<DirectoryEntry>
";
    $output .= "<Name>Mobile:</Name>
";
    $output .= "<Telephone>" . $result["mobile"] . "</Telephone>
";
    $output .= "</DirectoryEntry>
";
}
$output='</YealinkIPPhoneDirectory>
';

echo '$output';
?>

but i get this error message:

This page contains the following errors:

error on line 3 at column 8: Extra content at the end of the document
Below is a rendering of the page up to the first error.

$output

Answer 1

<?php

$conn=mysql_connect("localhost","user","********");
mysql_select_db("db_name",$conn);

header("Content-Type: text/xml");
header("Connection: close");
header("Expires: -1");

$output = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>
";
$output .= '<YealinkIPPhoneDirectory>
';
$sql="SELECT * from contacts ";
$rs=mysql_query($sql,$conn);
while($result=mysql_fetch_array($rs)) {
    $output .= "<DirectoryEntry>
";
    $output .= "<Name>Mobile:</Name>
";
    $output .= "<Telephone>" . $result["mobile"] . "</Telephone>
";
    $output .= "</DirectoryEntry>
";
}
$output.='</YealinkIPPhoneDirectory>';

echo $output;

?>