限制文件名匹配以特定方式启动

Question

I have thousands of files in a directory that i am running a batch script on to process.

The relevant files all start with XX-XX-XX (at least one integer, but no more than two, with underscores separating the three numbers)

I used txt2re to create this:

 $txt='1-2-3';

  $re1='(\\d+)';    # Integer Number 1
  $re2='(-)';   # Any Single Character 1
  $re3='(\\d+)';    # Integer Number 2
  $re4='(-)';   # Any Single Character 2
  $re5='(\\d+)';    # Integer Number 3

  if ($c=preg_match_all ("/".$re1.$re2.$re3.$re4.$re5."/is", $txt, $matches))
  {
      $int1=$matches[1][0];
      $c1=$matches[2][0];
      $int2=$matches[3][0];
      $c2=$matches[4][0];
      $int3=$matches[5][0];
      print "($int1) ($c1) ($int2) ($c2) ($int3) 
";
  }

Is it possible to get a slightly more compact version of this, that I can compare to the filename in a single function.

Answer 1

You could use

"/^\d\d?-\d\d?-\d\d?/"

If the digits are separated by underscores use _ instead of -.