as far as i studied in several posts, the following form should return to the div #CCC after submission
$editFormAction = $_SERVER['PHP_SELF']."#CCC";
if ((isset($_POST["MM_update"])) && ($_POST["MM_update"] == "formX")) {
$updateSQL = sprintf("UPDATE foodtable SET food_preference=%s WHERE food_id=%s",
GetSQLValueString($_POST['food_preference'], "text"),
GetSQLValueString($_POST['food_id'], "int"));
mysql_select_db($database_XYZ, $XYZ);
$Result1 = mysql_query($updateSQL, $XYZ) or die(mysql_error());
$updateGoTo = "preference.php";
if (isset($_SERVER['QUERY_STRING'])) {
$updateGoTo .= (strpos($updateGoTo, '?')) ? "&" : "?";
$updateGoTo .= $_SERVER['QUERY_STRING'];
}
header(sprintf("Location: %s", $updateGoTo));
exit ();
}
<body>
<div id ="AAA">
<p>Some text</p>
</div>
<div id ="BBB">
<p>Some more text</p>
</div>
<div id ="CCC">
<form action="<?php echo $editFormAction; ?>" method="post" name="formX" id="formX">
<table align="center">
<tr valign="baseline">
<td align="right" nowrap="nowrap">Update Food Name:</td>
<td><input type="text" name="food_name" value="" size="32" /></td>
</tr>
<tr valign="baseline">
<td nowrap="nowrap" align="right">
<input type="hidden" name="MM_update" value="formX" />
<input type="hidden" name="food_id" value="<?php echo $query['food_id']; ?>" />
</td>
<td>
<input type='submit' value='Update Food Name'/>"
</td>
</tr>
</table>
</form>
</div>
</body>
but it isn't returning to the div #CCC on submission. is there anything lacking in the above blocks of code?
thanks,
