doushu5451 2012-10-16 13:23
浏览 121
已采纳

PHP / MySQL字符串搜索查询

I've got a database setup with "customer" information. I've got a PHP form to search for the strings, first name (fname), last name (lname), and phone number (phone). For some reason, I'm not even getting the helpers displayed that the functions are working? I've re-read over this code over and over and can't seem to figure out where I'm missing something.

<form name="search" method="post" action="<?=$PHP_SELF?>">
 Seach for: <input type="text" name="find" /> in 
 <Select NAME="field">
 <Option VALUE="fname">First Name</option>
 <Option VALUE="lname">Last Name</option>
 <Option VALUE="phone">Phone #</option>
 </Select>
 <input type="hidden" name="searching" value="yes" />
 <input type="submit" name="search" value="Search" />
 </form>
 <? 
 //This is only displayed if they have submitted the form 
 if ($searching =="yes") 
 { 
 echo "<h2>Results</h2><p>"; 

 //If they did not enter a search term we give them an error 
 if ($find == "") 
 { 
 echo "<p>You forgot to enter a search term"; 
 exit; 
 } 

 // We preform a bit of filtering 
 $find = strtoupper($find); 
 $find = strip_tags($find); 
 $find = trim ($find); 

 //Now we search for our search term, in the field the user specified 
 $data = mysql_query("SELECT * FROM customer WHERE upper($field) LIKE'%$find%'"); 

 //And we display the results 
 while($result = mysql_fetch_array( $data )) 
 { 
 echo $result['fname']; 
 echo " "; 
 echo $result['lname']; 
 echo "<br>"; 
 echo $result['phone']; 
 echo "<br>"; 
 echo "<br>"; 
 } 

 //This counts the number or results - and if there wasn't any it gives them a little message explaining that 
 $anymatches=mysql_num_rows($data); 
 if ($anymatches == 0) 
 { 
 echo "Sorry, but we can not find an entry to match your query<br><br>"; 
 } 

 //And we remind them what they searched for 
 echo "<b>Searched For:</b> " .$find; 
 } 
 ?>
  • 写回答

2条回答 默认 最新

  • dongpeiwei8589 2012-10-16 13:33
    关注

    there are some errors in your script, i'll try to help you:

    <? --> <?php
    

    then your form passes parameters by method POST, so you have to check searching like this:

    if ($_POST['searching'] =="yes") 
    

    and you have the same error here:

    if ($_POST['find'] == "") 
    

    and here:

     $find = strtoupper($_POST['find']); 
    

    Bye!

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥20 怎么用dlib库的算法识别小麦病虫害
  • ¥15 华为ensp模拟器中S5700交换机在配置过程中老是反复重启
  • ¥15 java写代码遇到问题,求帮助
  • ¥15 uniapp uview http 如何实现统一的请求异常信息提示?
  • ¥15 有了解d3和topogram.js库的吗?有偿请教
  • ¥100 任意维数的K均值聚类
  • ¥15 stamps做sbas-insar,时序沉降图怎么画
  • ¥15 买了个传感器,根据商家发的代码和步骤使用但是代码报错了不会改,有没有人可以看看
  • ¥15 关于#Java#的问题,如何解决?
  • ¥15 加热介质是液体,换热器壳侧导热系数和总的导热系数怎么算