duanke3985 2012-07-15 03:22
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PHP解析错误:语法错误,意外T_VARIABLE [关闭]

Trying to get this code to work, but I keep running into errors. I am fairly new to PHP and doing a project for personal learning. Thank you in advance for any help!

If I cut the following code out it will run fine. The code with the ** is the code that is throwing the error.

[15-Jul-2012 03:10:01 UTC] PHP Parse error: syntax error, unexpected T_VARIABLE in x.php on line 22

var $salt = 'fortesting';
var $userpw = 'testing';
**var $saltpw = $salt . $userpw;**
var $tpw = hash('sha512', $saltpw, false);
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  • dongyi4170 2012-07-15 03:26
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    Seems like this is a part of properties class' declaration.

    Well, you can only specify constant value for properties. So you cannot concatenate strings there.

    The possible solution would be to initialize the saltpw property in runtinme in class' constuctor, like:

    public function __construct()
    {
        $this->saltpw = $this->salt . $this->userpw;
    }
    

    PS: var is obsolete, you should use private, protected or public instead

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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