使用PHP进行XML解析

Question

I have a .out file which has xml content like this.

<header stub>
    <article type="audio">
        <addedDate>2010-03-11 05:11:57</addedDate>
        <thumbnail>http://fgsdfff/4588/thumbnail_9.jpg</thumbnail>
        <asset="blarga.mp3" addedDate="2009-01-07 01:48:37">
            <size>3289048</size>
            <duration>206000</duration>
            <mime_type>audio/mpeg</mime_type>
        </asset>
    </article>
</footer stub>

1. I have to add <?xml version="1.0"?> and </xml> at the start of the xml and at the end respectively.
2. I have to replace <header stub> and </footer stub> with <channel> and </channel> tags respectively.
3. You might have noticed the XML is not well formed in the <asset> tag. It has to be like <asset url="blarga.mp3" addedDate="2009-01-07 01:48:37">. How do I add the url attribute?
4. In the thumbnail tag, i have to remove _9 from the jpg's name.

And finally, i have to convert the .out to .xml file.

Please help me with these

Answer 1

$content = file_get_content OR mysql_query;//"YOUR XML CONTENT FROM FILE OR MYSQL";
$content = "<?xml version="1.0"?>" . $content . "</xml>";
$content = str_replace("<header stub>", "<channel>", $content);
$content = str_replace("</footer stub>", "</channel>", $content);
$content = str_replace("<asset=", "<asset url=", $content);
$content = str_replace("thumbnail_9.jpg", "thumbnail.jpg", $content);