doulangxun7769 2011-02-11 18:33
浏览 32

PHP / MySQL / JSON编码帮助

I am trying to implement the auto-complete script from http://www.devbridge.com/projects/autocomplete/jquery/. It's asking for JSON output like:

{
 query:'Li',
 suggestions:['Liberia','Libyan Arab Jamahiriya','Liechtenstein','Lithuania']
}

I am using PHP/MySQL. My query to get the suggestions would be something like...

<?
$drug = $_GET['drug'];
$query = mysql_query("SELECT * FROM tags_drugs WHERE drug_name LIKE '$drug%'");
    while ($query_row = mysql_fetch_array($query))
        {
            $drug_name = $query_row['drug_name'];
        }

?>

This is where I'm stuck. How do I put the array $drug_name in the suggestions and encode it for json? Thanks in advance!

  • 写回答

2条回答 默认 最新

  • dsz90288 2011-02-11 18:37
    关注

    Use

    $drug_name[] = $query_row['drug_name'];
    

    instead of $drug_name = $query_row['drug_name'];

    Then use

    ?>
    <script type="text/javascript">    
        var drugName = <?php echo json_encode($drug_name);?>
    </script>
    

    Use this grugName variable in your JavaScript.

    评论

报告相同问题?

悬赏问题

  • ¥17 pro*C预编译“闪回查询”报错SCN不能识别
  • ¥15 微信会员卡接入微信支付商户号收款
  • ¥15 如何获取烟草零售终端数据
  • ¥15 数学建模招标中位数问题
  • ¥15 phython路径名过长报错 不知道什么问题
  • ¥15 深度学习中模型转换该怎么实现
  • ¥15 HLs设计手写数字识别程序编译通不过
  • ¥15 Stata外部命令安装问题求帮助!
  • ¥15 从键盘随机输入A-H中的一串字符串,用七段数码管方法进行绘制。提交代码及运行截图。
  • ¥15 TYPCE母转母,插入认方向