dtr87341 2015-10-13 21:22
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PHP / MYSQL / JSON:在IOS应用程序中调整解析api api

I am trying to follow this tutorial to parse a JSON web service for display in an app.

The tutorial takes the input for loans from a service called KIVA as follows:

{"loans":[{"id":961236,"name":"Alhassan","description":{"languages":["en"]},"status":"fundraising","funded_amount":0,"basket_amount":0,"image":{"id":1960690,"template_id":1},"activity":"Personal Purchases","sector":"Personal Use","themes":["Rural Exclusion"],"use":"to buy food and clothing, eliminating pressure to sell maize for low prices at harvest","location":{"country_code":"NG","country":"Nigeria","town":"Kaduna","geo":{"level":"town","pairs":"10 8","type":"point"}},"partner_id":288,"posted_date":"2015-10-13T21:00:03Z","planned_expiration_date":"2015-11-12T21:00:03Z","loan_amount":200,"borrower_count":1,"lender_count":0,"bonus_credit_eligibility":false,"tags":[]}

The current output from my service is:

[{"userid":"1","shcom":"hello","lcom":"hello there friend"}]

The main thing I think my web service is missing relative to the one above is:

"loans":`[ at the beginning of the output.

So I think what I need to do is insert that at the beginning of the JSON output as the objective-c code in the app uses "loans" to create an array as follows:

  NSArray* latestLoans = [json objectForKey:@"loans"]; // gets JSON

    NSLog(@"loans: %@", latestLoans); // Prints it

What would I need to do to my PHP code to print out JSON as in the tutorial?

Thanks for any suggestions:



while($row = mysql_fetch_assoc($res)) {
    $loans[] = $row;
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2条回答 默认 最新

  • douxu3732 2015-10-14 23:33

    The answer here was to change

    $loans[] = array('$loan);
    $loans[] = array('loans'=>$loan);

    This inserts the 'loans' at the beginning

    本回答被题主选为最佳回答 , 对您是否有帮助呢?



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