返回数组中相同id的多个值

Question

I'm pulling information from 3 different tables in MSSQL 2008 and I'd like to get the SUM of CC_qty as well as each Location condensed into one field per id. If this can be done in the query itself that would be fantastic - listagg and GROUP_CONCAT are not cutting it. Otherwise I've been working with array_reduce, array_merge, array_diff to no avail.

Here is my query and the original array:

SELECT a.id, a.qty, b.locationID, b.CC_qty, c.Location FROM (
  SELECT left(id, 10) as id, MAX(qty) as qty
  FROM db1
  WHERE id like 'abc-abc%'
  GROUP BY left(id, 10)
) as a
JOIN (
  SELECT locationID, left(SKU, 10) as SKU, CC_qty FROM db2
  WHERE CC_qty > 25
) as b on a.abc-abc = b.SKU
JOIN (
  SELECT locationID, Location FROM db3
) as c on b.locationID = c.locationID


Array
(
    [0] => Array
        (
            [id] => abc-abc-12
            [qty] => 0
            [locationID] => 276
            [CC_qty] => 250
            [Location] => NOP11
        )

    [1] => Array
        (
            [id] => abc-abc-12
            [qty] => 0
            [locationID] => 310
            [CC_qty] => 1385
            [Location] => NOP01
        )

    [2] => Array
        (
            [id] => abc-abc-23
            [qty] => 0
            [locationID] => 84
            [CC_qty] => 116
            [Location] => NOP06
        )

    [3] => Array
        (
            [id] => abc-abc-23
            [qty] => 0
            [locationID] => 254
            [CC_qty] => 432
            [Location] => NOP08
        )

    [4] => Array
        (
            [id] => abc-abc-23
            [qty] => 0
            [locationID] => 228
            [CC_qty] => 101
            [Location] => NOP04
        )

    [5] => Array
        (
            [id] => abc-abc-34
            [qty] => 0
            [locationID] => 254
            [CC_qty] => 436
            [Location] => NOP08
        )

    [6] => Array
        (
            [id] => abc-abc-34
            [qty] => 0
            [locationID] => 254
            [CC_qty] => 62
            [Location] => NOP08
        )

    [7] => Array
        (
            [id] => abc-abc-45
            [qty] => 0
            [locationID] => 75
            [CC_qty] => 89
            [Location] => NOP05
        )

    [8] => Array
        (
            [id] => abc-abc-45
            [qty] => 0
            [locationID] => 202
            [CC_qty] => 372
            [Location] => NOP07
        )

)

This is my desired output, for simplicity of knowing what information I absolutely require I've removed qty and locationID but those don't have to be removed:

 Array
    (
        [0] => Array
            (
                [id] => abc-abc-12
                [CC_qty] => 1635
                [Location] => NOP11, NOP01
            )

        [1] => Array
            (
                [id] => abc-abc-23
                [CC_qty] => 649
                [Location] => NOP06, NOP08, NOP04
            )

        [2] => Array
            (
                [id] => abc-abc-34
                [CC_qty] => 495
                [Location] => NOP08

        [3] => Array
            (
                [id] => abc-abc-45
                [CC_qty] => 461
                [Location] => NOP05, NOP07
            )

    )

Thanks for looking!

Answer 1

Being that I left an answer for MySQL, it wasn't going to work for this. I don't know MSSQL well enough to use it, so here's a way to do it with PHP so I don't leave you completely without an answer.

$arr = array
(
    array
    (
        'id' => 'abc-abc-12',
        'qty' => 0,
        'locationID' => 276,
        'CC_qty' => 250,
        'Location' => 'NOP11'
    ),
    array
    (
        'id' => 'abc-abc-12',
        'qty' => 0,
        'locationID' => 310,
        'CC_qty' => 1385,
        'Location' => 'NOP01'
    ),
    array
    (
        'id' => 'abc-abc-23',
        'qty' => 0,
        'locationID' => 84,
        'CC_qty' => 116,
        'Location' =>  'NOP06'
    )
);

$combinedArr = array();

foreach ($arr as $a)
{
    $found = false;

    foreach ($combinedArr as $i => $b)
    {
        if ($b['id'] == $a['id'])
        {
            $found = true;
            $locs  = explode(',', $a['Location']);

            $combinedArr[$i]['CC_qty'] += $a['CC_qty'];

            if (!in_array($b['Location'], $locs))
            {
                $locs[] = $b['Location'];
                $combinedArr[$i]['Location'] = implode(', ', $locs);
            }
        }
    }

    if (!$found)
        $combinedArr[] = $a;
}

print_r($combinedArr);

/*
Array
(
    [0] => Array
        (
            [id] => abc-abc-12
            [qty] => 0
            [locationID] => 276
            [CC_qty] => 1635
            [Location] => NOP01, NOP11
        )

    [1] => Array
        (
            [id] => abc-abc-23
            [qty] => 0
            [locationID] => 84
            [CC_qty] => 116
            [Location] => NOP06
        )

)
*/