dsdf64562672 2017-11-06 06:41 采纳率: 0%

# PHP，Jquery获取多个数组，组合一行

Concept: Adding Floors and Room counts and Room Numbers in a Hotel and saving it in a db

Front end Design:

Please have a look at this image

Backend what i am getting now:

`````` "floor" => array:3 [▼
0 => "3"
1 => "2"
2 => "1"
]
"room_count" => array:3 [▼
0 => "3"
1 => "3"
2 => "5"
]
"room_number" => array:11 [▼
0 => "101"
1 => "102"
2 => "103"
3 => "201"
4 => "202"
5 => "203"
6 => "101"
7 => "102"
8 => "103"
9 => "104"
10 => "105"
]
``````

The Question is:

How can i loop through to get:
Floor 3 has the room numbers 101, 102, 103
Floor 2 has the room numbers 201, 202, 203
Floor 1 has the room numbers 101, 102, 103, 104, 105

• 写回答

#### 1条回答默认 最新

• ds122455 2017-11-06 07:06
关注

Iterate through each floor, count the number of rooms, and then determine which room numbers are associated with that floor by working through the array of room numbers.

Given the array structure you're working with, the trick is that you'll need to have a loop like this one that can track the `\$prev_index` by incrementing `\$prev_index` by the room count at each floor.

``````<?php
\$array = array(
'floor' => array(
0 => '3',
1 => '2',
2 => '1',
),
'room_count' => array(
0 => '3',
1 => '3',
2 => '5',
),
'room_number' => array(
0  => '101',
1  => '102',
2  => '103',
3  => '201',
4  => '202',
5  => '203',
6  => '101',
7  => '102',
8  => '103',
9  => '104',
10 => '105',
),
);
for (\$prev_index = 0, \$i = 0; \$i < count(\$array['floor']); ++\$i) {
\$floor        = \$array['floor'][\$i];
\$room_count   = \$array['room_count'][\$i];
\$room_numbers = array_slice(\$array['room_number'], \$prev_index, \$room_count);
\$prev_index   = \$prev_index + \$room_count;

echo 'Floor '.\$floor.' has '.\$room_count.' rooms, with room numbers '.implode(', ', \$room_numbers)."
";
}
``````

``````Floor 3 has 3 rooms, with room numbers 101, 102, 103
Floor 2 has 3 rooms, with room numbers 201, 202, 203
Floor 1 has 5 rooms, with room numbers 101, 102, 103, 104, 105
``````
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