duanmu6231 2017-07-05 11:54
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为什么变量值未在插入查询中显示

I have this code snippet

$taskAssignedCompleteId = $row["TaskAssignCompletionId"];
echo "taskAssignedCompleteId::".$taskAssignedCompleteId. "
";

if($taskAssignedCompleteId == 0 || $taskAssignedCompleteId = null)
{
    echo "Currently no task assigned to you. If you are not doing a task on PMS and still receving this massage then, contact your team lead";
    return;
}

$sqlInsert = "INSERT INTO emp_task_finished_request (EmpTaskAssignCompletionId, RequestDateTime) VALUES (".$taskAssignedCompleteId.", '$date')";
echo "output : ".$sqlInsert;
$queryInsert = $connPDO->exec($sqlInsert);

    echo "
 output : ".$queryInsert;

Surprisingly $taskAssignedCompleteId value is not showing in query when i echo my $queryInsert varaiable while it is perfectly showing when i directly echo $taskAssignedCompleteId. Why is the problem? it is very strange for me. here is my output

taskAssignedCompleteId::13
sqlInsert full : INSERT INTO emp_task_finished_request (EmpTaskAssignCompletionId, RequestDateTime) VALUES (, '2017-07-05 16:53:45')
 output :
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3条回答 默认 最新

  • dongxi2163 2017-07-05 12:00
    关注

    You need to correct your if statement. $taskAssignedCompleteId = null is not correct. Kindly replace it by following

    if($taskAssignedCompleteId == 0 || $taskAssignedCompleteId == null)
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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