php foreach将2个数组合并为1行（工作日和数据）

Question

I have a problem with my current "Attendance Project", so I have 2 arrays.

• 1st array is to show a "workdays" the 1st array show only workdays in current month ex:April, so the result in my 1st array is (3,4,5,6,7,10,11,12,13,14,17,18,19,20,21,24,25,26,27,28)
• 2nd array is showing Employee Attendance in current month ex:April, so the result in my 2nd array is (17, 19)

here is my current code :

<table class="table table-striped table-bordered zero-configuration">
    <thead>
        <tr>
            <th style="width: 200px">Siswa</th>
            <!-- <?php for($i = 1; $i < 31; ++$i){?>
            <th><?= $i ?></th>
            <?php } ?> -->
            <?php foreach($workdays as $w){ ?>
            <th><?=$w;?></th>
            <?php } ?>
        </tr>
    </thead>
    <tbody>
        <?php 
        // for($x = 1; $x < 27; ++$x){
        foreach($records as $r){
        ?>
        <tr>
<td style="width: 200px"><?=$r->StudentName;?></td>
<?php
    ?>
    <?php 
         foreach($workdays as $w){
           foreach($tanggale as $t){ 

            if($w == $t){
            ?>
                <td style="background: #FFF000">M</td>
                <?php }else{ ?>
                <td style="background: #48C9A9">O</td>
                <?php } } } ?>
        </tr>
        <?php }  ?>
    </tbody>
</table>

It will produce :

I want value (17 and 19) will markup the data with yellow background, and the table is NOT out of range. Any help will appreciate..

Answer 1

Your code seems messy and I'm not gonna try to fix it on what you have, but I'll suggest solution:

1st - run foreach ($workdays as $w) and make header 2nd - run foreach ($workdays as $w) and make table-body like:

foreach ($workdays as $w) {
    if (in_array($w, $tanggale)) //if tanggle is the one with 17 and 19
    {
         //code
    }
    else
    {
         //code
    }
}