dongxing8766
2017-02-13 23:28
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输出JSON数组追加附加元素PHP

I'm pretty sure I'm quite close so hopefully quick answer.

I'm able to generate this JSON:

apps: [
    {
        0: {
            PublisherCount: "7"
    },
        Id: "87",
        AppName: "Productivity, Focus, Habits & Life Success by Audiojoy",
        AppBundle: "productivitymind"
    }
]

But I'm trying to get to:

apps: [
    {
        Id: "87",
        AppName: "Productivity, Focus, Habits & Life Success by Audiojoy",
        AppBundle: "productivitymind",
        PublisherCount: "7"
    }
]

Here is my output loop (I think the issue is in the 5th row where I array_push the new value for PublisherCount. It creates an additional node instead of adding it to the end.

$temp_array = array();
$i = 0;
while ($row = mysqli_fetch_assoc($publisher_apps)) {
$temp_array[] = $row;
$temp_array[$i][] = fetch_all(get_publisher_count_by_app_id($row['Id']))[0];
$i++;
}

$publisher_apps = $temp_array;

$result = array("apps"=>$publisher_apps);

output_json($result);

Thanks.

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我很确定我非常接近所以希望快速回答​​。 < p>我能够生成这个JSON:

  apps:[
 {
 0:{
 PublisherCount:“7”
},
 Id  :“87”,
 AppName:“Audiojoy的生产力,专注,习惯和生活成功”,
 AppBundle:“productivitymind”
} 
 
 
   
 
  

但我正试图去:

  apps:[
 {
 Id:“87”,
 AppName:“生产力,专注,习惯 &amp; Life Success by Audiojoy“,
 AppBundle:”productivitymind“,
 PublisherCount:”7“
} 
] 
   
 
 

这是我的输出 循环(我认为问题出在第5行,我在其中array_push PublisherCount 的新值。它创建了一个额外的节点,而不是将其添加到最后。

  $ temp_array = array(); 
 $ i = 0; 
while($ row = mysqli_fetch_assoc($ publisher_apps)){
 $ temp_array [] = $ row; 
 $ temp_array [$ i] [  ]  = fetch_all(get_publisher_count_by_app_id($ row ['Id']))[0]; 
 $ i ++; 
} 
 
 $ publisher_apps = $ temp_array; 
 
 $ result = array(“apps”=&gt;  ; $ publisher_apps); 
 
output_json($ result); 
   
 
 

谢谢。

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2条回答 默认 最新

  • drazvzi741287 2017-02-13 23:49
    最佳回答

    You have rows like this:

    ['Id' => "87",
     'AppName' => "Productivity, Focus, Habits & Life Success by Audiojoy",
     'AppBundle' => "productivitymind"]
    

    and fetch_all(get_publisher_count_by_app_id($row['Id']))[0] returns an array like this:

    ['PublisherCount' => 7]
    

    so when you append it with $temp_array[$i][], the entire array gets assigned to the 0 key of $temp_array[$i].

    There are various different ways you could get just the PublisherCount value. One way is to use array_merge to combine the result of get_publisher_count_by_app_id with $row, and then add the modified $row to your main array.

    while ($row = mysqli_fetch_assoc($publisher_apps)) {
        $count = fetch_all(get_publisher_count_by_app_id($row['Id']))[0];
        $temp_array[] = array_merge($row, $count);
    }
    

    If you do it this way, $i should become unneccessary.

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