duanchao9559 2016-11-26 14:47
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PHP Ver 7 - 未定义索引:吃 - 发布方法[重复]

I was making a simple form for getting data stored into variable.

My HTML Code:

<form class="form-horizontal" role="form" method="post" action="result.php">

    <div class="form-group">
      <label for="eat" class ="control-label col-md-3">Eating:</label>
        <div class="col-md-6">
            <input type="number" class="form-control" id="eating" placeholder="Hours Spent Eating Everyday">
        </div>
    </div> 
</form>

<div class="col-md-12">
<center><button type="submit" class="btn btn-default">Let's Know What You DID!</button></center>
</div>

MY PHP Code:

<?php 
$eat = $_POST["eating"];
?>

Error I'm Getting:

Notice: Undefined index: eating Notice: Undefined variable: eating Please help me out, I am using WAMP with Version 7 of PHP.

</div>
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2条回答 默认 最新

  • dongluzhi5208 2016-11-26 14:58
    关注

    In html:

    <input type="number" class="form-control" id="eating" placeholder="Hours Spent Eating Everyday" name="eating"> 
    

    In php

    If(isset($_POST["eating"])){
     $eating = $_POST["eating"];
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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