dslkchyv673627 2015-09-03 06:47
浏览 46
已采纳

使用ajax Php和mysql级联下拉列表

I am creating something like this and have a problem one of the dropdown. You get better understanding by the video

Video for the reference

here the source code file

here the tutorial link

  • 写回答

1条回答 默认 最新

  • douyinjiao9351 2015-09-03 07:55
    关注

    Each time you're receving the AJAX data, you're always adding it to the next dropdown. However, you're not clearing the dropdown before you do so, and therefore you get the previous items as well.

    To fix it for the Type->Model dropdowns for example (as shown in the video), you should start your populateModel() with an empty() call like this:

    function populateModel(xmlindata) {
    
      var mySelect = $('#printermodel');;
      mySelect.empty();
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?