试图获取非对象的属性 - Laravel

Question

There are lot of issues with this same topic but in my code, i don't see my error to be getting

Trying to get property of non-object

My models also seems alright. Could the issue results from my database relation?

Parents

  public function up()
    {

        Schema::create('parents', function (Blueprint $table) {
            $table->increments('id');
            $table->string('name');
            $table->string('phone');
            $table->integer('user_id')->unsigned()->nullable();
            $table->foreign('user_id')->references('id')->on('users')->onUpdate('cascade')->onDelete('cascade'); 

            $table->timestamps();
        });
    }

Child

public function up()
    {
        Schema::create('children', function (Blueprint $table) {
            $table->increments('id');
            $table->string('parent_phone')->references('phone')->on('parents')->onUpdate('cascade')->onDelete('cascade'); 
            $table->timestamps();
        });
    }

ChildModel

public function parents(){
      return $this->belongsTo(Parent::class, 'parent_phone');
  }

View

 @foreach ($item->parents as $parent)
        <td>{{ $parent->child }} <br/>
        <small>{{ $parent->created_at }}</small>
        <br>
        <small>{{ $parent->parents->name }}</small>

        </td>
      @endforeach

Answer 1

Your relationship is not quite right.

Because your foreign key (parent_phone) is not referencing the primary key (id) on the parents table, you need to specify the name of the field on parents that it references. This is done using the third parameter to the belongsTo() method. Your relationship should look like:

public function parents(){
    return $this->belongsTo(Parent::class, 'parent_phone', 'phone');
}

You can read more about Eloquent relationships in the documentation here.

Even after correcting the relationship, your view may still return this error because of this line:

{{ $parent->parents->name }}

If your parent record does not have a parent record, you will be attempting to access ->name on null, and that'll throw the error.