dougong9987 2017-11-16 22:53
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PHP提取MYSQL值问题

I have 2 tables: users and transactions

In users I have: userid, name, email

And in transactions I have: id, idsender, idreceiver

I want to make a log-table showing all the transactions and I want them to be displayed like: Transaction ID - SENDER'S NAME - RECEIVER'S NAME

I tried like this but it doesn't seem to work, at "Receiver" it doesn't show anything .. :

echo "<table>";
echo "<tr>";
echo "<th>Transaction ID</th>";
echo "<th>Sender</th>";
echo "<th>Receiver</th>";
echo "</tr>";

    $resultuser = mysqli_query($conn, "SELECT * FROM users"); 
    $rowuser=mysqli_fetch_array($resultuser);

    $resulttrans = mysqli_query($conn, "SELECT * FROM transactions"); 
    $rowtrans=mysqli_fetch_array($resulttrans);



    $ress=mysqli_query($conn, "SELECT * FROM transactions");

            while($row=mysqli_fetch_array($ress)){
                echo "<tr>";
                echo "<td>".$row['id']."</td>";
                echo "<td>"." same as receiver"."</td>";
            $receiver=mysqli_query($conn, "SELECT name FROM users WHERE userid='" . $rowtrans['idreceiver'] . "'");
            $receivername = mysqli_fetch_array($receiver);

                echo "<td>". $receivername ."</td>";
                echo "</tr>";
            }
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2条回答 默认 最新

  • drjgk44268 2017-11-16 23:14
    关注

    Don't use two queries. Join the two tables in one query:

    $ress = mysqli_query("SELECT t.id, u1.name AS sendername, u2.name AS receivername
        FROM transactions AS t
        JOIN users AS u1 ON u1.userid = t.idsender
        JOIN users AS u2 ON u2.userid = t.idreceiver");
    while ($row = mysqli_fetch_assoc($ress)) {
        echo "<tr>";
        echo "<td>".$row['id']."</td>";
        echo "<td>" . $row['sendername'] ."</td>";
        echo "<td>" . $row['receivername'] . "</td>";
        echo "</tr>";
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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