PHP preg_match（）或strpos来检查字符串是否以substring开头

Question

I am changing views of a page depending the $_GET['code'] it can equal a series of different codes but they will all start with either Red, Town or Bearing, then a series of characters.

For example, the following would all trigger the condition

RedWings-223123-NY
Townmansion-2341322-KY
BearingWays-23422-DC

I have tried

<?php if(preg_match("%(?=.*Bear)(?=.*Red)(?=.*Town)%", $_GET['code'])): ?>

   <span> new view </span>

<?php endif ?>

and

<?php if( strpos($_GET['code']), "Red" ) !== false) || strpos($_GET['code']), "Bear" ) !== false || strpos($_GET['code']), "Town" ) !== false)): ?>

   <span>new view</span>

<?php endif ?>

Answer 1

Your strpos is incorrect syntactically, you close the functions before passing the term to search for.

Your regex requires all terms be present and doesn't check for the start of the string. You need to use an or and a leading anchor. This:

^(?:Bear|Town|Red)

should do it.

Regex Demo: https://regex101.com/r/civdig/3/

Correct strpos usage:

<?php if( strpos($_GET['code'], "Red" ) === 0 || strpos($_GET['code'], "Bear" ) === 0 || strpos($_GET['code'], "Town" === 0)): ?>

   <span>new view</span>

<?php endif ?>

You need the 0 to confirm it matches, otherwise you are checking that it is somewhere in there.