按钮类型=使用php isset提交而不是输入类型按钮[复制]

Question

This question already has an answer here:

• <button> vs. <input type=“button” />. Which to use? 14 answers

I have been searching this stuff but could not find anywhere. when i search about button name and value, everywhere its mentioned about input type=button

But i am looking for button type=submit instead of input type=button i want to allow users to remove their comments. So, the delete button is just showing like a link

The Html is

<button class="likeslink" type="submit" name="delcom" value="<?php echo $comid ?>"><small>Delete</small></button>

I am not getting how can i check if this button is clicked or not not using php as i tried

<?php
if(isset('delcom'))
{
$sql = "DELETE FROM comments WHERE id = :id";
$stmt = $DB->prepare($sql);
$stmt->bindValue(":id", $comid);
$stmt->execute();
}
?>

But its not working.

Meanwhile, i want a popup alert message that confirms Delete Query includings Delete or Cancel buttons on it

I don't want that simple javascript alert on the top of the page. I want some popup window in the middle of the screen with my own Color scheme

Please help

</div>

Answer 1

Make sure to get it from the POST variable to check. This is probably what you're actually intending on doing.

<?php
    if(isset($_POST['delcom']))
    {
        $sql = "DELETE FROM comments WHERE id = :id";
        $stmt = $DB->prepare($sql);
        $stmt->bindValue(":id", $comid);
        $stmt->execute();
    }
?>