使用php检查复选框的值

Question

I want to check the checkBox's value in php. Either selected or not. I am trying in a way;

JQuery

<script type="text/javascript">

    $(document).ready(function(){
        $("#save").click(function(){
            var checkBox = $("#boxV").is(':checked');

            $.ajax({
                url: "http://localhost/testing/test.php",
                type:"POST",
                async:true,
                data:{
                    "done":1,
                    "checkBox" : checkBox
                },
                success: function(data){
                        $('#result').append(data);
                }   
            });
        });
    });



 </script>

PHP

<?php
    if(!isset($_POST['checkBox'])){
        echo ('0');
    }else{
        echo ('1');
    }
    ?>

HTML

 <li><input type="checkbox" id = "boxV" > Check</li><br>

The problem is that both times (Selected , not selected) the result div is filled with 1. Is there any problem?

Answer 1

You can pass checkBox variable conditionally as describe below:

$(document).ready(function(){
        $("#save").click(function(){
            var checkBox = $("#boxV").is(':checked');
            if(checkBox) {
                var data = {
                   'done': 1,
                   'checkBox': checkBox 
                };
            }else{
                 var data = {
                   'done': 1,                       
                 };
            }
            $.ajax({
                url: "http://localhost/testing/test.php",
                type:"POST",
                async:true,
                data:data,
                success: function(data){
                     $('#result').append(data);
                }   
            });
        });
    });