dongwupei7803 2017-02-16 10:10
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将函数返回值分配给类[duplicate]中的受保护变量

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use config;
class abc extends xyz{
    protected $adminMail = config('deployment.adminemail');

    public function xyz(){
     ......
    }
}

It gives me syntax error for line protected "$adminMail = config('deployment.adminemail'); of (;)"

I know this question is not very logical but please guide where I am getting confused.

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  • dongyong3590 2017-02-16 10:20
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    This should do the trick for you, as far as config() is implemented in the right way.

    use config;
    class abc extends xyz{
        protected $adminMail;
    
        public function __construct() {
          $this->adminMail = config('deployment.adminemail');
        }
    
        public function xyz(){
         ......
        }
    }
    

    Explanation: You cannot use an expression as a default value, because class variables are initiated before runtime. Means only scalar types like a string or an integer are allowed as default value. The only way to archive this ist within the constructor.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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