将字符串从内部函数追加到父变量

Question

I have a function and want to gather it's output log to email when done. It looks something like this:

function blabla() {
   $emailMessage = "some text";

   $emailMessage .= "some more text";

   function foo() {
     for ($x = 1; $x <= 20; $x++) {
        $emailMessage .= 'Call #' . $x;
        // then doing an API call
        return $response; 
     }
   }

   $res = foo();

   $emailMessage .= "last line of text";

}

Now $emailMessage looks like this: some text || some more text || last line of text. The text from the inner function is not appended.

How can I get it to look like this: some text || some more text || call #1 || call #2 ||... || last line of text

------EDIT------

Thanks to @kamal pal I used a global variable. Result looks like this:

function blabla() {
       global $emailMessage;
       $emailMessage = "some text";

       $emailMessage .= "some more text";

       function foo() {
         global $emailMessage;
         for ($x = 1; $x <= 20; $x++) {
            $emailMessage .= 'Call #' . $x;
            // then doing an API call
            return $response; 
         }
       }

       $res = foo();

       $emailMessage .= "last line of text";

    }

Answer 1

It's due to scope, Child function has it's own scope.

I can think of two options to accomplish this task:

• Using Global Variable
• Passing as Ref argument (see example below)

---

function blabla() {
    $emailMessage = "some text".PHP_EOL;
    $emailMessage .= "some more text".PHP_EOL;

    function foo(&$emailMessage) { // passed as ref argument
     for ($x = 1; $x <= 20; $x++) {
            $emailMessage .= 'Call #' . $x.PHP_EOL;
            // then doing an API call
            //return $response; //it will exit function
     }
    }

    $res = foo($emailMessage);

    $emailMessage .= "last line of text".PHP_EOL;
    return $emailMessage;

}
echo blabla();

Demo: https://eval.in/571036